Execute one step after the iterator is done

I have an iterator over a list.

I would like to execute one step after the iterator is done.

In analogy to a loop I am trying to achieve this:

for x in [a,b,c, ...]
{
append x to Gsheet
}
end for
send webhook

Maybe this demo can help you: https://demo.heradiensten.nl/s/share/5590654/vuxhr9t43fo9wozu9f83

Thank you very much for your reply.
I read your demo.

If I understand correctly, what you have is analog to
**begin pseudo code**
for x in [a,b,c, ...]
{
block A of steps
}
**end pseudo code**
so "block A of steps" is executed n times

Did I understand that correctly?

I am looking for a way to achieve
**begin pseudo code**
for x in [a,b,c, ...]
{
block A of steps
}
block B of steps
**end pseudo code**

so "block A of steps" is executed n times
and afterwards
"block B of steps" is executed once.

How would I need to modify your demo to achieve that?
Thank you very much

Step 4 is iterator.
Step 5 is, look if that field is already present. So for you it might be a sheet lookup. Because if its there already, why add it
Thats step 6 in my workflow, route 1 is edit the found row in spreadsheet
route 2 is add a row in spreadsheet

@Andreas I understand now, after a router you cant create a step.
So basiccally you want to add a stepp for the last field in iterator.
Not sure how that can be done, depends if the iterator also has a counts for all fields inside it.
@Pabbly is it possible to counts all fields before router and then add a step if entry last is done then send webhook (api)

Otherwise a solution can be to do send webhook (api) before the router and add a delay in the next webhook/api.

@Hermes Yes, that's exactly what I am trying to achieve. Thank you very much

@Hermes Yes, that's exactly what I am trying to achieve. Thank you very much

In my step 3 I got a field that stated: Total = 155
Before the router step need to create a field that counts
Router step 3 would then be if count =155 then send webhook

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@Hermes Thank you very much. I will try that! Thank you very much again for your time.

I believe this 1 should work to count all entries in the iterator

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